To pirnt the nth element of Arithmetic progression

Question - 

Given the first element and d of an Arithmetic progression , you have to find the nth element of that progression.

Example - 

Input : a=1, d=2, n=6

Ouptut : 11

Approach - 

We know the basic formula to find the nth element of any arithmetic progression is Tn= (a+(n-1)*d)

Implementation - 

//To find the nth element of any Arithmetic progression

#include<iostream>

using namespace std;

int print(int a,int d,int n)

{

    int Tn;

    Tn=a+(n-1)*d;

    return Tn;

}

int main()

{

    int a,d,n;

    cout<<"\t\t\tArithmetic progression  "<<endl;

    cout<<"Enter a : ";cin>>a;

    cout<<"Enter d : ";cin>>d;

    cout<<"enter n(term) : ";cin>>n;

    int Tn=print(a,d,n);

    cout<<"nth term of this progression is : "<<Tn<<endl;

    return 0;

}

code on compiler

Time complixity - O(1)