To print the Arithmetic progression

Question - 

Given the value of a, d and number of terms(n). you have to print the Arithmetic progression.

Example -

Input : a=1, d=1 ,n=5

Output : 1, 2, 3, 4, 5

Input : a=2, d=2 ,n=10

Output : 2, 4, 6, 8, 10, 12, 14, 16, 18, 20

Approach - 

nth term of any Arithmetic progression is a+(n-1)*d.

Implementation - 

//To print Arithmetic progression

#include<iostream>

using namespace std;

void print(int a,int d,int n)

{

    for(int i=1;i<=n;i++){

        cout<<(a+(i-1)*d)<<" "; 

        

    }

}

int main()

{

    int a,d,n;

    cout<<"\t\t\tArithmetic progression  "<<endl;

    cout<<"Enter a : ";cin>>a;

    cout<<"Enter d : ";cin>>d;

    cout<<"enter n(term) : ";cin>>n;

    print(a,d,n);

    return 0;

}

Code on compiler

Time complixity - O(n)